NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

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NCERT Solutions For Class 6 Maths Practical Geometry Exercise 14.2

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Exercise 14.2

Ex 14.2 Class 6 Maths Question 1.
Draw a line segment of length 7.3 cm using ruler.
Solution:
Step I: Mark at point P.
Step II : Place the O mark of the ruler against the point P.
Step III : Mark a point Q at a distance of 7.3 cm from P.
Step IV : Join P and Q.
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry
Thus \overline { PQ }is the line segment of length 7.3 cm.

Ex 14.2 Class 6 Maths Question 2.
Construct a line segment of length 5.6 cm using ruler and compass.
Solution:
Step I: Draw any line L of suitable lengths.
Step II : Place the needle of the compass on the zero mark of the ruler and open it upto 5.6 mark.
Step III : Place the needle at any point A at the line and draw an arc to cut l at B.

NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry
Thus, \overline { AB }is the required line segment of length 5.6 cm.

Ex 14.2 Class 6 Maths Question 3.
Construct \overline { AB }of length 7.8 cm. From this, cut off \overline { AC }of length 4.7 cm. Measure \overline { BC }.
Solution:
Given that \overline { AB }= 7.8 cm and \overline { AC }= 4.7 cm.
Step I : Place zero mark of the ruler at A.
Step II : Mark a point B at a distance of 7.8 cm from A.
Step III : Mark another point C at a distance of 4.7 cm from A such that AC = 4.7 cm.
Step IV : On measuring the length of BC, we find that \overline { BC }= 3.1 cm.
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry

Ex 14.2 Class 6 Maths Question 4.
Given \overline { AB }of length 3.9 cm. Construct \overline { PQ }such that the length of \overline { PQ }is twice that of \overline { AB }. Verify by measurement.
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry
(Hint : Construct \overline { PX }such that the length of \overline { PX }= length of \overline { AB }then cut off \overline { XQ }such that \overline { XQ }also has the length of \overline { AB }.
Solution:
Step I: Draw a line l of suitable length.
Step II: Draw \overline { AB }= 3.9 cm
Step III: From the line, construct \overline { PX }= \overline { AB }= 3.9 cm.
Step IV: Again construct \overline { XQ }= \overline { AB }=3.9 cm
Verification: \overline { PX }+ \overline { XQ }= \overline { AB }+ \overline { AB }
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry
Thus twice of \overline { AB }is equal to \overline { PQ }

Ex 14.2 Class 6 Maths Question 5.
Given \overline { AB }of length 7.3 cm and \overline { CD }of length 3.4 cm, construct a line segment \overline { XY }such that the length of XY is equal to the difference between the length of \overline { AB }and \overline { CD }. Verify the measurement.
Solution:
Step I : Construct \overline { AB }= 7.3 cm and \overline { CD }= 3.4 cm.
NCERT Solutions For Class 6 Maths Chapter 14 Practical Geometry
Step II: Take a point P on the given line l.
Step III: Construct \overline { PR }such that \overline { PR }= \overline { AB }= \overline { AB }= 7.3 cm.
Step IV:Construct \overline { RQ }= \overline { CD }= 3.4 cm such that PQ = \overline { AB }\overline { CD }.
Verification : On measuring, we observe that \overline { PQ }= 3.9 cm = 7.3 cm 3.4 cm.
= \overline { AB }\overline { CD }
Thus, \overline { PQ }= \overline { AB }\overline { CD }.

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