CBSE Class 9 Maths Chapter 7 Notes Heron’s Formula

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CBSE Class 9 Maths Chapter 7 Notes Heron’s Formula

Heron’s Formula Class 9 Notes Understanding the Lesson

1. Area of triangle with base ‘b’ and altitude ‘h’ is
Area = \(\frac{1}{2}\)(b x h)

Heron’s Formula Class 9 Notes Maths Chapter 7 1

2. Area of an isosceles triangle with equal sides ‘a’ each and third side b is
Area \(=\frac{b}{4} \sqrt{4 a^{2}-b^{2}}\)
Heron’s Formula Class 9 Notes Maths Chapter 7 .2

3. Area of an equilateral triangle with side ‘a’ each is
Area=\(\frac{\sqrt{3}}{4} a^{2}\)
Heron’s Formula Class 9 Notes Maths Chapter 7 .3

4. Area of a triangle by Heron’s formula when sides a, b and c are given is
Area = \(\sqrt{s(s-a)(s-b)(s-c)}\)
Where s = semi-perimeter = \frac{a+b+c}{2}
Heron’s Formula Class 9 Notes Maths Chapter 7 .4

5. Area of rhombus
Area= \(\frac{1}{2} d_{1} \times d_{2}\)
where d1 and d2 are the lengths of its diagonals.
Heron’s Formula Class 9 Notes Maths Chapter 7 .5

6. Area of trapezium
Area=\(\frac{1}{2}\) (a+b) h
where a and b are parallel sides and h is distance between two parallel sides.

Heron’s Formula Class 9 Notes Maths Chapter 7 .6

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